Rabbit Analysis :: essays research papers

In the poem, â€Å"Rabbit,† the topic is rabbits which represent children and how they can be prey for one group and play for another. In addition to the rabbits representing children, I think that the child in the poem represents a parental figure and the dogs represent people in the outside world.   Ã‚  Ã‚  Ã‚  Ã‚  This is supported in the theme which states that children should not be in such a rush to grow up because the outside world can be a cruel place. For example, â€Å"the dogs don’t hate [them], merely want to / taste the cider of [their] blood, watch [their] / fur drift lazily toward October clouds / where geese infuriate them† (11-14). This is a supporting text because it shows that children won’t always be treated fairly and if they are in such a rush to grow up, they could face many problems early in life because they can feel as though they do not belong anywhere. Also, this quotation is descriptive and works well in that it allowed me to paint a picture of how other people could perceive children as helpless and a form of easy bait. To them, children are not just other humans; they are a source of adventure and game. Furthermore, it says â€Å"better that you hop directly back / demand your cage†¦Ã¢â‚¬  (7-8), which maintains that i f the children are not protected and sheltered by their parents, their fate could become as bad as what is described above; they could live a life in which the end of the negative path seems endless. It is saying that the one place a child can feel safe is in or at his/her house where he/she has â€Å"†¦ cedar chips, the water bottle full / and dripping next to wilted greens†¦Ã¢â‚¬  (8-9). It may not be the first place a child would want to go back to when he/she is in trouble but the option will always there. This house is the child’s safe haven and protection from the outside world; a place to feel safe, protected, and nourished. For example, the â€Å"†¦children bring you apples. / They’ll rub your fur and bring / another and another† (19-21). This text shows that no matter what happens the parents will be there to show care and love for their children without asking any questions. I like how the author worded the three quotes from above.

Patterns Within Systems of Linear Equations

Jasmine Chai Grade 10 196298501 Patterns within systems of linear equations Systems of linear equations are a collection of linear equations that are related by having one solution, no solution or many solutions. A solution is the point of intersection between the two or more lines that are described by the linear equation. Consider the following equations: x + 2y = 3 and 2x – y = -4. These equations are an example of a 2Ãâ€"2 system due to the two unknown variables (x and y) it has. In one of the patterns, by multiplying the coefficient of the y variable by 2 then subtract the coefficient of x from it you will be given the constant.As a word equation it can be written like so with the coefficient of x as A and coefficient of y as B and the constant as C, 2B – Ax = C. This can be applied to the first equation (x + 2y = 3) as 2(2) – 1 = 3. To the second equation (2x – y = -4), it is -1(2) – 2 = -4. By using matrices or graphs, we can solve this syst em. Regarding other systems that also has such as pattern, it should also have the same solution as the two examples displayed. For instance, 3x + 4y = 5 and x -2y = -5, another system, also displays the same pattern as the first set and has a solution of (-1, 2).Essentially, this pattern is indicating an arithmetic progression sequence. Arithmetic progression is described as common difference between sequences of numbers. In a specific sequence, each number accordingly is labelled as an. the subscript n is referring to the term number, for instance the 3rd term is known as a3. The formula, an = a1 + (n – 1) d, can be used to find an, the unknown number in the sequence. The variable d represents the common difference between the numbers in the sequence. In the first equation (x + 2y = 3) given, the common differences between the constants c – B and B – A is 1.Variable A is the coefficient of x and variable b represents the coefficient of y, lastly, c represents the constant. The common difference of the second equation (2x – y = -4) is -3 because each number is decreasing by 3. In order to solve for the values x and y, you could isolate a certain variable in one of the equations and substitute it into the other equation. x + 2y = 3 2x – y = -4 x + 2y = 3 * x = 3 – 2y * 2(3 – 2y) – y = -4 * 6 – 4y – y = -4 * 6 – 5y = -4 * -5y = -10 * y = 2 Now that the value of y is found, you can substitute 2 in as y in any of the equations to solve for x. x + 2y = 3 x + 2(2) = 3 * x + 4 = 3 * x = 3 – 4 * x = -1 Solution: (-1, 2) Even though the solution has already been found, there are many different ways to solve it, such as graphically solving it. By graphing the two linear lines, you can interpolate or extrapolate if necessary to find the point where the two lines intersect. | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | Graph 1 Graph 1 | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | Just from the equations given, it is not in a format where it can be easily graphed. By changing it into y=mx + b form, the first equation will result as y = – (1/2) x + 3/2 or y = -0. 5x + 1. 5 and the second equation will result as y = 2x + 4. The significance of the solution is that it is equal to the point of intersection as shown on Graph 1. This can then allow the conclusion that the solution of the two linear equations is also the point of intersection when graphed. According to this arithmetic progression sequence, it could be applied to other similar systems.For instance, the examples below demonstrates how alike 2Ãâ€"2 systems to the previous one will display a similarity. Example 1: In the first equation the common difference between (3, 4 and 5) is 1. In the second equation, the common differen ce is -3. The common differences in these equations are exact to the previous example. 3x + 4y = 5 x – 2y = -5 x – 2y = -5 * x = 2y – 5 (Substitution) 3x + 4y = 5 * 3(2y – 5) + 4y = 5 * 6y – 15 + 4y = 5 * 10y – 15 = 5 * 10y = 20 * y = 2 (Substituting y) x – 2y = -5 * x – 2(2) = -5 * x – 4 = -5 * x = -5 +4 * x = -1 Solution: (-1, 2)Example 2: In the first equation below, it has a common difference of 18 for (2, 20 and 38). For the second equation, in (15, -5 and -25), it has a common difference of -20. In this example, the system is solved graphically. 2x + 20y = 38 15x – 5 y = -25 Solution: (-1, 2) | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | Graph 2 Graph 2 | | |From the examples given above that are very similar to the first system, we can conclude that there is something common between them, that is the point of intersection or the values of x and y. That would imply that the x and y values and the point of intersection will always be (-1, 2) for all systems that follow arithmetic progression sequences. Due to that similarity, an equation that can be applied to these types of equations can be made. If the first coefficient of the first equation is identified as A and the common difference is c, an equation such as, Ax + (A + c) y = A + 2c, is made.This equation is so, because it is describes an arithmetic sequence, where the coefficients and constant are increasing by one in response to the coefficient before. In the second equation of the system, another equation can be made relatively the same to the first, with exceptions of different variables used. If B is used to represent the first coefficient of the second equation and d is used as the common difference, the equation, Bx + (B + d) y = B + 2d is created. With 2 equations, we have now created a system; to solve the system we can use the elimination method.This method is used to eliminate certain variables in order to find the value of another variable. After doing so, you could substitute in the value for the found variable and solve for the other(s). Ax + (A + c) y = A + 2c Bx + (B + d) y = B + 2d In order to use the elimination method, you must make the coefficient of x or y the same depending on which one you would like to eliminate. In this case, we will start by eliminating x. To proceed to do so, we must first multiply the first equation by B and the second equation by A: ABx + (AB + Bc) y = AB + 2Bc ABx + (AB + Bd) y = AB + 2BdAfter we have made the coefficient of x the same for both equations, we can now subtract the equations from one another: ABx + ABy + Bcy = AB + 2Bc ABx + ABy + Bdy = AB + 2Bd * Bcy – Bdy = 2Bc – 2Bd To find the val ue of y, we must isolate the variable y. Bcy – Bdy = 2Bc – 2Bd * y(Bc – Bd) = 2(Bc – Bd) * y = 2 Now that the value of y is found, to find the value of x is to substitute the value of y, which is 2, into any equation that includes that variable x and y. Bx + (B + d) y = B + 2d * Bx + (B + d) 2 = B + 2d * Bx + 2B + 2d = B + 2d * Bx + 2B – B = 2d – 2d * Bx + B = 0 * Bx = -B * x = -1To conclude the results of the equations above, it is making thee statement that all 2Ãâ€"2 systems that display an arithmetic progression sequence, which has a common difference between the coefficients and constant, it will have a result, point of intersection, of (-1, 2). To confirm that this is correct, the example systems below will demonstrate this property: Equation 1 (common difference of 8): 2x + 10y = 18 Equation 2 (common difference of 3): x + 4y = 7 Substitution Method x + 4y = 7 * x = 7 – 4y Substitute 2x + 10y = 18 * 2 (7 – 4y) + 10y = 1 8 * 14 – 8y +10y = 18 * 14 + 2y = 18 2y = 18 – 14 * 2y = 4 * y = 2 Substitute x + 4y = 7 * x + 4(2) = 7 * x + 8 = 7 * x = 7 – 8 * x = -1 Solution: (-1, 2) Once again from the example above, it displays that the solution or the point of intersection is identified as (-1, 2). From previous examples, all have a common difference that is different from the other equation involved in that system. In the following example, it will experiment whether having the same common difference will make a difference in the result. Equation 1 (common difference of 3): 2x + 5y = 8 Equation 2 (common difference of 3): x + 3y = 6 Graph 3 Graph 3As you can see on the graph, it shows that the two lines do not intersect at (-1, 2) even though it is a 2Ãâ€"2 system that has a common difference in both equations, meaning that the intersection at (-1, 2) can only be applied to systems that has 2 different common differences. To conclude, all 2Ãâ€"2 systems that follow arithmetic progres sion sequence with different common difference have a solution of (-1, 2). Furthermore, now that it is known that there is a certain pattern for a specific type of system, if this property is applied to a 3Ãâ€"3 system, with 3 different variables can it still work?Consider the following 3Ãâ€"3 system, (x + 2y + 3z = 4), (5x + 7y + 9z = 11) and (2x + 5y + 8z = 11). In this system, it has similar patterns to the 2Ãâ€"2 systems above due to its arithmetic progression. In the first equation, it has a common difference of 1 and the second equation has a common difference of 2 and lastly, the third equation has a common difference of 3. To solve this system, we can solve it using the method of elimination or matrices. Equation 1 (common difference: 1): x + 2y + 3z = 4 Equation 2 (common difference: 2): 5x + 7y + 9z = 11Equation 3 (common difference: 3): 2x + 5y + 8z = 11 Elimination Method To eliminate the variable x, we must first start by making the coefficients of x in two equations the same. We can do so by finding the lowest common multiple of the two coefficients and multiplying the whole equation by it. Equation 1: x + 2y + 3z = 4 * 2(x + 2y + 3z = 4) * 2x + 4y + 6z = 8 We can eliminate the variable x now that the coefficients of x in both equations are the same. To eliminate x, we can subtract equation 3 from equation 1. Equation 1 and 3: 2x + 4y + 6z = 8 2x + 5y + 8z = 11 -y -2z = -3 After eliminating x from two equations to form another equation that does not involve x (-y -2z = -3), another equation that does not involve x must be made to further eliminate another variable such as y or z. Equation 1: x + 2y + 3z = 4 * 5(x + 2y + 3z = 4) * 5x + 10y + 15z = 20 We can eliminate the variable x now that the coefficients of x in both equations are the same. To eliminate x, we can subtract equation 2 from equation 1. Equation 1 and 2: 5x + 10y + 15z = 20 – 5x + 7y + 9z = 11 3y + 6z = 9Now that two different equations that do not involve x ((-y -2z = -3 ) and (3y + 6z = 9)) are created, we can find the common coefficient of y and eliminate it to find the value of the variable z. Let (-y -2z = -3) to be known as equation A and (3y + 6z = 9) will be known as equation B. Equation A: -y -2z = -3 * 3(-y -2z = -3) * -3y -6z = -9 Equation A and B: -3y -6z = -9 + 3y + 6z = 9 0 = 0 As you can see from the result, 0 = 0, this is indicating that the system either has many solutions, meaning a collinear line or no solution, where all the lines do not intersect together at a specific point.Even if you attempt to isolate a different variable it will still have the same result. For instance, using the same equations above, you eliminate the variable y first as displayed below. Equation 1 (common difference: 1): x + 2y + 3z = 4 Equation 2 (common difference: 2): 5x + 7y + 9z = 11 Equation 3 (common difference: 3): 2x + 5y + 8z = 11 Elimination Method Equation 1: x + 2y + 3z = 4 * 7(x + 2y + 3z = 4) * 7x +14y + 21z = 28 Equation 2: 5x + 7y + 9z = 1 1 * 2(5x + 7y + 9z = 11) * 10x + 14y + 18z = 22 Equation 1 and 2: 7x +14y + 21z = 28 – 10x + 14y + 18z = 22 3x + 3z = 6 Equation 1: x + 2y + 3z = 4 * 5(x + 2y + 3z = 4) * 5x +10y + 15z = 20 Equation 3: 2x + 5y + 8z = 11 * 2(2x + 5y + 8z = 11) * 4x + 10y +16z = 22 Equation 1 and 3: 5x +10y + 15z = 20 – 4x + 10y +16z = 22 x – z = -2 Two equations have been made that has already eliminated the variable y. Let (-3x + 3z = 6) be equation A and let (x – z = -2) be equation B. Doing this, is in attempt to solve for variable x. Equation A: -3x + 3z = 6 Equation B: x – z = -2 * 3(x – z = -2) * 3x – 3z = -6 Equation A and B: -3x + 3z = 6 + 3x – 3z = -6 0 = 0As you can see the result, it is the same even if you try to solve another variable, from that we can confirm that this system has either no solution or infinite solutions, meaning that they are collinear lines. Furthermore, because this is a 3Ãâ€"3 system, meaning that it has three different variables, such as x, y and z, graphing it will also be very different from a graph of a 2Ãâ€"2 system. In a 3Ãâ€"3 system, the graph would be a surface chart, where the variable z allows the graph to become 3D. From this, we can conclude 3Ãâ€"3 systems that follow an arithmetic progression will always have either no solution or infinite solutions.This is saying that all linear equations do not intersect together in one point or they do not intersect. A way to prove this is through finding the determinant. The determinant is a single number that describes the solvability of the system. To find the determinant of all 3Ãâ€"3 systems that possesses arithmetic progression, we can start by creating a formula. Allow the first coefficient of the first equation be A and the second equation’s first coefficient be B and lastly, the first coefficient of the third equation be C.The common difference of equation one will be c, the common difference of equation two will be d, and the common difference of equation e will be e. This can be described through the following equations: 1. Ax + (A + c) y + (A + 2c) z = (A + 3c) 2. Bx + (B + d) y + (B + 2d) z = (B + 3d) 3. Cx + (C + e) y + (C + 2e) z = (C + 3e) When developing a matrix to find the determinant, you must have a square matrix. In this case, we do not have a square matrix. A square matrix is where the number of rows and columns are equal, for example, it could be a 2Ãâ€"2, 3Ãâ€"3, or 4Ãâ€"4. Looking at the equations, it is a 3Ãâ€"4 matrix; as a result it must be rearranged.Below is the rearranged matrix of the equations above. x A (A + c) (A + 2c) (A + 3c) y B (B + d) (B + 2d) = (B + 3d) z C (C + e) (C + 2e) (C + 3e) To find the determinant, you must find 4 values from the 3Ãâ€"3 matrix that helps find the determinant of A, B and C. In this case, if you were to find the values for A, you would cover the values that are in the same row and column as A, like so, A (A + c) (A + 2c) B (B + d) (B + 2d)C (C + e) (C + 2e) You would be left with four separate values that can be labelled as A, B, C and D. Respectively to the model below: a b c d In order to find the determinant you must find the four values for A, (A + c) and (A +2c). To find the determinant the equation ad – cb is used. The equation in this situation would be like the one below: A[(B + d)(C + 2e) – (C + e)(B + 2d)] – (A + c)[B(C + 2e) – C(B + 2d)] + (A +2c)[B(C + 2e) – C(B + 2d)] Expand * = A(BC – BC + Cd – 2Cd + 2Be – Be + 2de – 2de) – (A + c)(BC – BC + 2Be – 2Cd) + (A + 2c)(BC – BC + 2Be – 2Cd) Simplify 2ABe – 2ABe + 2ACd – 2ACd + 2Ccd – 2Ccd + 2Bce – 2Bce * = 2ABe – 2ABe + 2ACd – 2ACd + 2Ccd – 2Ccd + 2Bce – 2Bce * = 0 As it is visible, above it shows that the determinant found in this type of matrix is zero. If it is zero, it means that there are infinite an swers or no answer at all. Using technology, a graphing calculator, once entering a 3Ãâ€"3 matrix that exhibits arithmetic progression, it states that it is an error and states that it is a singular matrix. This may mean that there is no solution. To conclude, there is no solution or infinite solution to 3Ãâ€"3 systems that exhibit the pattern of arithmetic sequencing.This can be proved when the sample 3Ãâ€"3 system is graphed and results as a 3D collinear segment. As well as the results from above when a determinant is found to be zero proves that 3Ãâ€"3 systems that pertains an arithmetic sequence. Arithmetic sequences within systems of linear equations are one pattern of systems. Regarding other patterns, it is questionable if geometric sequences can be applied to systems of linear equations. Consider the following equations, x + 2y = 4 and 5x – y = 1/5. It is clear that the coefficients and constants have a certain relation through multiplication.In the first equation (x + 2y = 4), it has the relation where it has a common ratio of 2 between numbers 1, 2 and 4. For the second equation (5x – y = 1/5), it has a common ratio of -1/5 between 5, -1 and 1/5. The common ratio is determined through the multiplicative succession from the previous number in the order of the numbers. When the equations are rearranged into the form y=mx+b, as y = – ? x + 2 and y = 5x – 1/5, there is a visible pattern. Between the two equations they both possess the pattern of the constant, where constant a is the negative inverse of constant b and vice versa.This would infer that if they are multiplied together, as follows (-1/2 x 2 = -1 and 5 x -1/5 = -1), it will result as -1. With equations that are also similar to these, such as the following, y = 2x – 1/2, y = -2x + 1/2, y = 1/5x – 5 or y = -1/5x +5. Displayed below, is a linear graph that shows linear equations that are very similar to the ones above. Graph 4 Graph 4 From the graph a bove, you can see that the equations that are the same with exceptions of negatives and positives, they reflect over the axis and displays the same slope.For instance, the linear equations y = 2x -1/2 and y=-2x +1/2 are essentially the same but reflected as it shows in the graph below. Also, all equations have geometric sequencing, which means that they are multiplied by a common ratio. Secondly, the points of intersection between similar lines are always on the x-axis. Graph 5 Graph 5 Point of intersection: (0. 25, 0) Point of intersection: (0. 25, 0) To solve a general 2Ãâ€"2 system that incorporates this pattern, a formula must be developed. In order to do so, something that should be kept in mind is that it must contain geometric sequencing in regards to the coefficients and constants.An equation such as, Ax + (Ar) y = Ar2 with A representing the coefficients and r representing the common ratio. The second equation of the system could be as follows, Bx + (Bs) y = Bs2 with B as the coefficient and s as the common ratio. As a general formula of these systems, they can be simplified through the method of elimination to find the values of x and y. Ax + (Ar) y = Ar2 Bx + (Bs) y = Bs2 Elimination Method B (Ax + (Ar) y = Ar2) * BAx + BAry = BAr2 A (Bx + (Bs) y = Bs2) * ABx + ABsy = ABs2 Eliminate BAx + BAry = BAr2 – ABx + ABsy = ABs2 BAry – ABsy = BAr2 – ABs2 ABy (r – s) = AB (r2 – s2) * y = (r + s) Finding value of x by inputting y into an equation ABx + ABsy = ABs2 * ABx + ABs(r + s) = ABs2 * ABx = ABs2 – ABs(r +s) * x = s2 – s(r +s) * x = s2 – s2 – rs * x = rs To confirm that the formula is correct, we can apply the equation into the formula and solve for x and y and compare it to the results of graph 4. The equations that we will be comparing will be y = 5x – 1/5 and y = -1/5x + 5. The point of intersection, (1, 4. 8) of these equations is shown graphically on graph 4 and 6. The common rat io (r) of the first equation is -0. and the common ratio, also known as s in the equation of the second equation is 5. X = – (-0. 2 x 5) = 1 Y = (-0. 2 + 5) = 4. 8 As you can see, above, the equations are correctly matching the point of intersection as shown on the graphs. Due to such as result, it is known that it can now be applied to any equations that display geometric sequencing. Graph 6 Graph 6 Resources: 1. Wolfram MathWorld. Singular Matrix. Retrieved N/A, from http://mathworld. wolfram. com/SingularMatrix. html 2. Math Words. Noninvertible Matrix. Retrieved March 24, 2011 from, http://www. mathwords. com/s/singular_matrix. htm

Writing and Colonial New England

Men were not responsible for anything that went on in the house back in that time. Married and divorced parents spent more time now with their children than 40 years ago. Children time for fathers Increased a lot more now than in the colonial times. Fathers weren't responsible for their children and women were obligated to do all house work. Response: This particular article took me by surprise because the fact that back in Colonial times fathers didn't really help around the house is upsetting and surprising.In my opinion, women and men are obligated to do the same and equal work as catheter. The Role of Men and Women In Colonial New England: Summary: Women and Men were forbidden to strike each other in the Colonial times. A man was forced to give bond if he was caught verbally abusing his wife. The duty of a husband was to go work and support his wife at all times. Women's property was forced to be given up to her husband once they were married and she was not allowed to work or ow n anything. In men's pollen women lacked strength for Intellectual exercise.Response: This article shocked me because the fact that men saw themselves as better than women is extremely degrading and unfair, women can do the same wings men can do The Role of Children In Colonial New England: Summary: Puritan parents were obligated to direct their children responsibly. Children who were too spoiled were sent to be treated by a master to become more obedient. Girls started learning house work as young as the age of 5. They had to learn how to cook and clean and do all the kinds of housework.I feel like with time writing exams you are so rushed to finish writing and outline that by the time you start your essay you Just go blank. To prevent that I read my articles more than once to completely understand it thoroughly and then I begin my essay. This really helps me in the long run and is good or completing and understanding my essay. Log 1 felt like I was prepared for the midterm. If I w ere to change anything I would read my articles a few more times next time to better understand them before my midterm.But generally I felt like I did a exceptional Job on my midterm and tried my hardest spending all the time I could to finish it. Writers Checklist: 1 . Does your idea draft respond fully to the assignment? Yes, it does. 2. Are your ideas organized the way you want? Yes, in my opinion, the ideas are organized how I want them to be. 3. Does your intro explain what the essay is about and what its repose is? My essays introduction introduces the topic and explains what the essay is going you be about. . Do you have a thesis that states your point or indicates the issue the essay will address? Yes, my thesis indicates the issue that my essay will address. 5. Do the body paragraphs each have a topic sentence? Do they develop the main points by giving specifics and examples to support these points? Yes. 6. Does your conclusion make one or more recommendations? Yes, my conc lusion makes at least one recommendation. 7. Yes, both my trusted friend and a classmate has reviewed my essay.

Eleemosynary, A Full-Length Play by Lee Blessing

Eleemosynary, A Full-Length Play by Lee Blessing It might be best to begin your approach to this play by learning how to pronounce the title and understanding the meaning of this vocabulary word. In this dramatic work by Lee Blessing, three generations of highly intelligent and freethinking women attempt to reconcile years of family dysfunction. Dorothea was a repressed housewife and mother of three sons and a daughter, Artemis (Artie), whom she favored. She discovered that being an eccentric suited her perfectly and spent a lifetime thrusting her wild ideas and beliefs onto an unappreciative and doubting Artemis. Artemis ran away from Dorothea as soon as she could and kept on the move until she married and had a daughter of her own. She named her Barbara, but Dorothea renamed the child Echo and began to teach her everything from Ancient Greek to calculus. What Echo loves most is words and spelling. The title of the show comes from the winning word that Echo spelled correctly at the National Spelling Bee. The play jumps backward and forward in time. As one character relives a memory, the other two play themselves as they were during that time. In one memory, Echo portrays herself as a three-month-old. At the beginning of the play, Dorothea has suffered a stroke and is bedridden and catatonic for several scenes. Throughout the play, however, she takes part in her memories and then transitions back to the present, trapped in her minimally responsive body. The director and actors in Eleemosynary have the challenge of making these memory scenes feel authentic with smooth transitions and blocking. Production Details The production notes for Eleemosynary are specific regarding set and props. The stage needs to be filled with an abundance of books (signifying the sheer brilliance of these women), a pair of homemade wings, and perhaps a real pair of scissors. The rest of the props may be mimed or suggested. Furniture and sets should be as minimal as possible. The notes suggest only a few chairs, platforms, and stools. Lighting should consist of   â€Å"ever shifting areas of light and darkness.† The minimal set and the stress on lighting serve to assist the characters in moving between memories and the present time, allowing focus to be on their stories. Setting: Various rooms and locales Time: Now and then Cast size: This play can accommodate 3 female actors. Roles Dorothea is a self-acknowledged eccentric. She uses her eccentricity as a means to escape the judgment and pressures of a life she didn’t choose. Her desire was to influence her daughter to embrace her way of life, but when her daughter runs from her, she refocuses her attention on her granddaughter. Artemis has a perfect memory. She can remember anything and everything with total accuracy. She has two desires in life. The first is to research and find out everything she possibly can about this world. The second is to be as far away from her mother (in both body and spirit) as possible. She believes in her heart that she failed Echo and that failure can never be undone, just as she can never forget a single detail of her life. Echo has a mind to equal both her mother’s and grandmother’s. She is fiercely competitive. She loves her grandmother and wants to love her mother. By the end of the play, she is determined to use her competitive nature to mend her relationship with her elusive mother. She will no longer accept Artemis’s excuses for failing to be a mother to her. Content issues: Abortion, abandonment Resources You can watch a director and some actors discuss and rehearse the play.The  Dramatist Play Service holds the production rights for Eleemosynary.

A Profile of Byzantine Emperor Alexios Komnenos

A Profile of Byzantine Emperor Alexios Komnenos Alexius Comnenus, also known as  Alexios Komnenos, is perhaps best known for seizing the throne from Nicephorus III and founding the Comnenus dynasty. As emperor, Alexius stabilized the government of the empire. He was also Emperor during the First Crusade. Alexius is the subject of a biography by his learned daughter, Anna Comnena. Occupations: EmperorCrusade WitnessMilitary Leader Places of Residence and Influence: Byzantium (Eastern Rome) Important Dates: Born: 1048Crowned: April 4, 1081Died: Aug. 15, 1118 About Alexius Comnenus Alexius was the third son of John Comnenus and a nephew of Emperor Isaac I. From 1068 to 1081, during the reigns of Romanus IV, Michael VII, and Nicephorus III, he served in the military; then, with the help of his brother Isaac, his mother Anna Dalassena, and his powerful in-laws the Ducas family, he seized the throne from Nicephorus III. For more than half a century the empire had suffered from ineffective or short-lived leaders. Alexius was able to drive the Italian Normans from western Greece, defeat Turkic nomads whod been invading the Balkans, and halt the encroachment of the Seljuq Turks. He also negotiated agreements with Sulayman ibn Qutalmà ¯sh of Konya and other Muslim leaders on the empires eastern border. At home he strengthened the central authority and built up military and naval forces, thus increasing imperial strength in portions of Anatolia (Turkey) and the Mediterranean. These actions helped stabilize Byzantium, but other policies would cause difficulties for his reign. Alexius made concessions to powerful landed magnates which would serve to weaken the authority of himself and future emperors. Although he maintained the traditional imperial role of protecting the Eastern Orthodox Church and repressed heresy, he also seized funds from the Church when necessary, and would be called to account for these actions by the ecclesiastical authorities. Alexius is well known for appealing to Pope Urban II for help in driving the Turks from Byzantine territory. The resulting influx of Crusaders would plague him for years to come.

(not deciding) Essay Example | Topics and Well Written Essays - 1500 words

(not deciding) - Essay Example These paintings all belong to high Renaissance style because they demonstrate unity in pictorial representation. These paintings represent religious characters and themes in naturalistic landscapes, vibrant colors, strong contour lines, contrapposto posing, realistic figures in stable composition with an implicit triangular format, and combined linear and aerial perspectives, although Madonna and Child with Saints and Angels and Madonna and Child with St. Jerome look flatter due to the use of tempera, Madonna and Child with Saints and Angels is less realistic with the addition of angels and halos, and The Flight into Egypt has a stronger three-dimensional form, with soft, glowing colors and shadows that create chiaroscuro effect. These paintings represent religious characters and themes, although Madonna and Child with Saints and Angels is less realistic with the addition of angels and halos. In Madonna and Child with St. Jerome, the three religious characters are Mary, the child Jesus, and St. Jerome. It appears that St. Jerome has visited the mother and child with some solemn or sad news because of the serious, somewhat sad, mood of the latter. In Madonna and Child with Saints and Angels, the religious characters are more numerous, which include Mary, child Jesus, Mary Magdalene, John the Baptist, Jerome, Francis, and Christopher, and two angels. The scene is naturalistic in how the main front characters are doing realistic actions, although the religious theme is apparent in how they all show adoration to the child Jesus, while Francis is experiencing stigmata at the back. The Flight into Egypt features Mary, Joseph, and the child Jesus. The biblical event is their travel to Egypt. These paintings employ religious characters and themes that were prominent subjects of the painters’ times. Apart from the portrayal of religious characters and themes, these paintings are all set in naturalistic landscapes. None of the

The Business Relationship between Nathan and Frank Essay

The Business Relationship between Nathan and Frank - Essay Example Ethical codes seek to set standards of fair and reasonable behavior throughout the supply chain, or in the attitude towards the employee or customer. Application: Application of the law is complicated by reality, because as the case of Frank and Nathan shows, a business is by nature made up of many different individuals. Moral and economic values differ from person to person within a business situation. A business is a large organizational structure, and within this structure, there may be individuals who are inspired to behave unethically for any number of reasons—here, we are not given Frank’s reasons, but he is clearly going back on his word and breaking his promise about payment, which is unethical. He has his own reasons. Many of these reasons have to do with the goals of the individual. For example, if a person views monetary gain as their main purpose, they may be willing to put ethical issues aside in order to reach their goal with maximum efficiency, to reach their short term goals and gain advantage. They may not pay attention to the code of ethics at all, and I think this is something Frank did in the cas e. Conclusion: One potential obstacle to a strictly legal solution is that, despite the prevalence of scientific and then panoptic programs throughout the twentieth century, corruption has continued to be a strong force in the business landscape including restaurant supply and services. Part of this may be habitual: much of the graft that goes on in this environment is accepted as a sort of ritual that is basically harmless, or â€Å"honest graft.† Issue 1: Frank is certainly not showing appropriate management in his conduct towards a valued customer who is supposed to receive a discount. Then again, it could also be argued that Nathan was not being ethical either, because he did not double check, get a paper